Question

Integration of cot inverse under root 4 x minus x square upon x minus 2

Answer 1

Step-by-step explanation:

cot^-1(1-x+x^2)

=tan^-1(1/(1-x+x^2)

=tan^-1[(x+1-x)/1-x(1-x)

=tan^-1(x)+tan^-1(1-x) 

hope this helps you