integration of cot sqr x
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cosec sqr x -1
this is your answer
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All I can tell you is that the Trig identity:
cot^2(x) = csc^2(x)-1
and the indefinite integral of csc^2(ax) = -cot(ax)/a
therefore:
the integral[cot^2(x)] = integral[csc^2(x)] - integral[1]
which yields your answer of cotx - x
cot^2(x) = csc^2(x)-1
and the indefinite integral of csc^2(ax) = -cot(ax)/a
therefore:
the integral[cot^2(x)] = integral[csc^2(x)] - integral[1]
which yields your answer of cotx - x
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