Question

Integration of cotx into log(sinx)

Answer 1

Putting log(sinx ) = t Differentiating wrt x on both sides Cot x dx = dt So ultimate result after substituton Integration t dt = t^2 /2 + c = {Log(sin x)}^2 /2 + c

Answer 2

dif: of sinx is cosx
sinx/cosx where dif: of sinx is cosx
formula: cotx = cosx/sinx i.e.., f(x) g(x) where....dif: of g(x) = f(x) so. it is equal to log g(x) :- integration of cotx is log |sin x .