Physics, asked by supreeth77, 7 months ago

integration of d\dx (xsinx)

Answers

Answered by bhupesh05raut

2

Answer:

∫ xsinx dx = -xcosx - ∫ (-cosx) dx.

= -xcosx - (-sinx) + C (where C is the constant of integration)

= sinx - xcosx + C

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