Physics, asked by cdiya1958, 3 months ago

integration of d²v/dt² dt​

Answers

Answered by ramesh015
1

Answer:

Lets keep it simple.

Differentiation of x is one. So vice versa, i.e. integration of 1 is x.

So, d(dx/dt)/dt = integral of (-x)

I.e. dx/dt = -x^ 2/2

Since integration of x^n is x^n+1 / n+1

Now again integrate both side so we get,

y = - x^3 / 2* 3 = - x^3/6

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cdiya1958: but it's d²v/dt²
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