integration of d²v/dt² dt
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Lets keep it simple.
Differentiation of x is one. So vice versa, i.e. integration of 1 is x.
So, d(dx/dt)/dt = integral of (-x)
I.e. dx/dt = -x^ 2/2
Since integration of x^n is x^n+1 / n+1
Now again integrate both side so we get,
y = - x^3 / 2* 3 = - x^3/6
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cdiya1958:
but it's d²v/dt²
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