Integration of dx/(ax+b)
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Answer:
1/a log(ax+b)
Step by Step Solution :
We have to find the integration of :
dx/(ax+b) .... (1)
As we know that :
Integration of dx/x = logx
Let, ax+b = t
On differentiate with respect to 't' both the side : adx = dt => dx = dt/a
On putting the value of 'dx' in equation (1) :
dt/a.t [ because ax+b = t ]
1/a × dt/t
=> 1/a × integration of dt/t
=> 1/a×logt
=> 1/a log(ax+b)
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