Question

integration of dx by 1-cos^2 x

Answer 1

Answer :

Now,

$\int \frac{dx}{1 - {cos}^{2}x } \\ \\ = \int \frac{dx}{ {sin}^{2}x } \\ \\ = \int {cosec}^{2} x \: dx \\ \\ = - \int( - {cosec}^{2} x) \: dx \\ \\ = - cotx \: + c$

where c is integral constant

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