integration of DX by root of 3 square + 4
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The answer is.........
given ,
y = inte {dx/ [โ(3)^4]}
inte. w . r .t .x
inte(dx/ (3)^2)
( (3)^(-2)). + c
( (3)^(-1)/-1). + c
1/(-3)
1/-3
mark as brainliest.
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given ,
y = inte {dx/ [โ(3)^4]}
inte. w . r .t .x
inte(dx/ (3)^2)
( (3)^(-2)). + c
( (3)^(-1)/-1). + c
1/(-3)
1/-3
mark as brainliest.
=
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