integration of dx/x^1/2(5-x)^1/2
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integration of dx/x^1/2(5-x)^1/2. Asked by Balbir | 5th Oct, 2017, 12:11: PM. Expert Answer: begin mathsize 16px style integral fraction numerator dx over denominator square root of straight x open ...
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Answer:- - 1/2root5x^3/2 +1/10(5-x)^3/2
Step-by-step explanation:Given
dx/root x(5-x) is differentiated bt after sperating it by partial method
The method is as follow
1/root x(5-x)=A/root x +B/root(5-x).......... 1eqn
1=A root(5-x)+B root x
On taking root(5-x)=0
Gives x=root 5
Putting value in eqn give
1=B(root(root5)
B=1/5
Putting rootx x =0
Gives A=1/root 5
Putting the value of A and B in eqn 1
1/root 5x+1/5root(5-x)
Now differentiating
=dx/root 5x +dx/5 root(5-x)]
=1/root 5(-1/2x^3/2) + 1/5(-1/2)(-1/(5-x)^3/2)
= - 1/2root5 x^3/2 + 1/10(5-x)^3/2
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