Integration of e^2x in the limits -infinity to zero
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Now,
∫ e^(2x) dx
= 1/2 e^(2x), since ∫ e^(mx) dx = 1/m e^(mx)
Now, using the limits (- ∞ to 0), we get the integral value as
= 1/2 [ e^(2 × 0) - e^{2 × ( -∞)} ]
= 1/2 [ e^0 - e^( - ∞ ) ]
= 1/2 (1 - 0), since e^(- ∞) = 0
= 1/2
#MarkAsBrainliest
Now,
∫ e^(2x) dx
= 1/2 e^(2x), since ∫ e^(mx) dx = 1/m e^(mx)
Now, using the limits (- ∞ to 0), we get the integral value as
= 1/2 [ e^(2 × 0) - e^{2 × ( -∞)} ]
= 1/2 [ e^0 - e^( - ∞ ) ]
= 1/2 (1 - 0), since e^(- ∞) = 0
= 1/2
#MarkAsBrainliest
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