integration of e^2x.logx
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In general ∫(eαx)dx=1αeαx
Explanation:
∫10e−2xdx=−12e−2x∣10=−12(e−2−1)
Explanation:
∫10e−2xdx=−12e−2x∣10=−12(e−2−1)
komaljangra:
can't get it
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