Math, asked by komaljangra, 1 year ago

integration of e^2x.logx

Answers

Answered by shweta77

2

In general ∫(eαx)dx=1αeαx

Explanation:

∫10e−2xdx=−12e−2x∣10=−12(e−2−1)

komaljangra: can't get it

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