Question

Integration of e^(ln2+lnx)

Answer 1

Answer:

x²

Step-by-step explanation:

let y=e^(ln2+lnx)

=e^(ln2x)

y=2x

so ∫ydx=∫y2x dx

=2*x¹⁺¹/(1+1)

=2/2*x²

=x²