Question

integration of e^x/(a+be^x)^1/2​

Answer 1

to find: integral of e^x/(a+be^x)

let t=e^x

dt= e^x dx

substituting these values in the integral:

=dt/a+bt

take 1/a+b outside the integral

=dt/t

=log |t|/a+b +C

=log |e^x|/a+b +C

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