Integration of e^xln(a)
Attachments:
Answers
Answered by
1
Answer:
he integral of e^x(ln x+1/x) is of the form
I=∫ex(lnx+1x)dx
Using the following formula for integration
∫ex[f(x)+f′(x)]dx=exf(x)+c
Here we have the given function f(x)=lnx, and differentiate with respect to variable x we have f′(x)=1x
Now using the formula
∫ex[f(x)+f′(x)]dx=exf(x)+c
I=ex(lnx)+c⇒∫ex(lnx+1x)dx=exlnx+c
Step-by-step explanation:
Similar questions