Math, asked by vimaljoshi4167, 1 month ago

Integration of e^xln(a) ​

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Answered by shersinghmeena1127
1

Answer:

he integral of e^x(ln x+1/x) is of the form

I=∫ex(lnx+1x)dx

Using the following formula for integration

∫ex[f(x)+f′(x)]dx=exf(x)+c

Here we have the given function f(x)=lnx, and differentiate with respect to variable x we have f′(x)=1x

Now using the formula

∫ex[f(x)+f′(x)]dx=exf(x)+c

I=ex(lnx)+c⇒∫ex(lnx+1x)dx=exlnx+c

Step-by-step explanation:

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