Math, asked by navy8070, 1 year ago

Integration of e^xloga+e^alogx+e^aloga

Answers

Answered by Geekydude121
27

This is a very easy integration...and the solution of the problem is given below..

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Answered by abhi178
16
we have to find \int{e^{xloga}+e^{alogx}+e^{aloga}}\,dx

or, \int{a^x+x^a+a^a}\,dx


we know, \int{a^x}\,dx=\left[\frac{a^x}{lna}\right]+C

\int{x^n}=\left[\frac{x^{n+1}}{n+1}\right]+C

so,
\int{a^x+x^a+a^a}\,dx\\\\\\=\int{a^x}\,dx+\int{x^a}\,dx+\int{a^a}\,dx\\\\\\=\left[\frac{a^x}{lna}\right]+\left[\frac{x^{a+1}}{a+1}\right]+a^ax+C
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