integration of g'(x)÷(g(x))^2 dx=
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it is given that 
Let g(x) = P
differentiate with respect to x both sides,
g'(x) = dP/dx
so, g'(x).dx = dP ......(i)
now,
=
+ C
= -
+ C
now, put P = g(x)
so,
= -1/g(x) + C
Let g(x) = P
differentiate with respect to x both sides,
g'(x) = dP/dx
so, g'(x).dx = dP ......(i)
now,
=
= -
now, put P = g(x)
so,
sai123456789:
thanks
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