Question

integration of limits 0 to 90degrees under root 1minus sin2x dx​

Answer 1

Answer:

Step-by-step explanation: √1-sin2x

Write sin2x as 2sinxcox and 1 as (sinx)*2 +(cosx)*2

The expression becomes √{sinx -cosx}*2= sinx - cosx

Now follow the method of normal integration i.e. integration of sinx is - cosx and that of cosx is sinx