Math, asked by amar1180, 11 months ago

integration of ln(1/e^x)dx​

Answers

Answered by dharmikbanka23
1

Answer:

ln(1/e^x) = ln(e^-x)

= -xlne

= -x

[Assume '|' to be integration symbol]

Now,

|-xdx = -x^2/2 + C

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