Question

Integration of logx/x .dx

Answer 1

$\textbf{Check the Attachment}$⬆⬆⬆



Be Brainly.



@karangrover12.

Answer 2

Hello!

$\int \sf \dfrac{\sf log\:x}{\sf x}.dx$

Then,
Differentiate both sides w.r.t. $\bf\small{x}$ :

$\dfrac{1}{\sf x} = \dfrac{\sf dt}{\sf dx} \\ \\ \implies \dfrac{1}{\sf x}. \sf dx = dt \\ \\ \implies \int \sf t.dt \implies \dfrac{\sf t^{2}}{2} + \sf C \implies \boxed{\red{\bf{\dfrac{1}{2}(\sf log\:x)^{2} + \sf C}}}$

Cheers!