Question

integration of one upon X square + 8 DX​

Answer 1

Answer:

x^3/3 + 8 X + c

here c is constant

Answer 2

Step-by-step explanation:

$∫\frac{1}{ {x}^{2} } + 8 \: dx \\ ∫{x}^{ - 2} + 8 \: dx \\ \\ ( {x}^{ - 1} + 8x) + c \\ \\ \frac{1}{x} + 8x + c$