Question

integration of root(1+ 4x)​

Answer 1

Answer:

Check the attachment for the answer...

Hope this helps you...

Answer 2

Answer:

$\frac{1}{6}(4x+1)^{3/2}$

Step-by-step explanation:

take

$1 + 4x = t$

so,

$\frac{dt}{dx} = \frac{d}{dx} (1 + 4x) \\ \frac{dt}{dx} = 4 \\ dx = \frac{dt}{4}$

Using this

Int ($\sqrt{4x + 1}$)dx

= Int ($\sqrt{t}$)dt/4

=$\frac{t^{3/2}}{3/2} * \frac{1}{4}$

=$\frac{1}{6}(4x+1)^{3/2}$