Question

integration of s/(s^2+4) ds

Answer 1

it should be your answer.

Answer 2

Answer:

$\frac{1}{2}\ln (s^2 + 4) + C$

Step-by-step explanation:

Given problem,

$\int \frac{s}{s^2+4}ds----(1)$

Let $s^2 + 4 = t$

On differentiating,

$2sds = dt$

$\implies sds = \frac{dt}{2}$

From equation (1),

$\frac{1}{2}\int \frac{dt}{t}$

By integrating,

$\frac{1}{2}\ln t+ C$

$\frac{1}{2}\ln |s^2 + 4| + C$