integration of sec^2x/tanx
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Answer:
You have to remeber that
sec 2 ( x ) is the derivative of tan ( x )
Explanation:
So:
∫ sec 2 x tan x d x = ∫ tan x d ( tan x ) = tan 2 x 2
Step-by-step explanation:
You can also see this this way:
∫ sec ^2 x tan x d x = ∫ sec x ( sec x tan x ) d x
If u = sec x then d u = sec x tan x d x
so = ∫ u d u = u 2 2 = sec 2 x 2 + C
This is equivalent to the other answer of tan 2 x 2 + C because tan
2 x and sec 2 x are only a constant away from one another through the equality tan 2 x + 1 = sec 2 x .
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