Integration of [sec²(2tan^-1(x))]/(1+x²)
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Answered by
0
Answer:
hygrometer
Step-by-step explanation:
hygrometer
Answered by
0
Answer:
ANSWER
I=∫
1+x
2
sec
2
(2tan
−1
x)
dx
Let 2tan
−1
x=t. Then,
d(2tan
−1
x)=dt
1+x
2
2
dx=dt
dx=
2
1+x
2
dt
Putting 2tan
−1
x=t and dx=
2
1+x
2
dt, we get,
I=∫
1+x
2
sec
2
t
×
2
1+x
2
dt
I=
2
1
∫sec
2
t dt
I=
2
1
tant+C
I=
2
1
tan(2tan
−1
x)+C
Step-by-step explanation:
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