Question

integration of . [secx(secx + tanx)].dx

Answer 1

this is answer ..........

Answer 2

HELLO DEAR,

GIVEN function is ∫[secx(secx + tanx)].dx

now, ∫(sec²x + secx tanx).dx

∫sec²x.dx + ∫secxtanx.dx

we know d(tanx)/dx = sec²x
and d(secx)/dx = secx.tanx

HENCE,

⇒ tanx + secx + c

hence, the integral of secx(secx + tanx) = (tanx + secx)

I HOPE ITS HELP YOU DEAR,
THE