Question

integration of secx+ tanx​

Answer 1

∫(sec(x)+tan(x))dx

= ∫ 1/(sec(x) - tan(x)) dx, after multiplying the top and the bottom by sec(x) - tan(x) and using the identity sec^2(x) = tan^2(x) + 1

= ∫cos(x)/(1 - sin(x)) dx

= ∫-1/(1 - sin(x)) d(1- sin(x)), mental substitution, or you can let u = 1-sin(x)

= -ln(1-sin(x)) + c

Answer 2

$here is your answer$

$secx+tanx$

$-secx$

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