Question

integration of secxcosecx/log(tanx)​

Answer 1

Answer:log(log tan x)

Step-by-step explanation:

secxcosecxdx/log (tan x)

If we take log tan x=t

1/tanx×sec^2xdx=dt

dx=tanx dt/sec^2 x

(sec x cosecx tanxdt)/sec^2x t

cancelling everything we get

Integral(dt/t)=log t

log(log tan x)

Answer 2

Answer:

hlo hii

I don't know sorry