Integration of (sin^-1x+cos^-1x)^2
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Answer:
Step-by-step explanation:
11- x²
* A * (sin?(1 – 2x2) + cos-(241 – 32)]da
use formula sin-1x + cos-lx =
78* val] - cos -1(1 – 2x2) + – sin -1(2xv1 – x2)]dx
va [1 – 2 cos +1(x) – 2 sin = 2(x)]dx
to
x= [1 – 2(cos –+(x) + sin –+(x)]dx
4x4 [1 – 2 x []dx
= 0
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