Math, asked by vibdibs734, 10 months ago

Integration of (sin^-1x+cos^-1x)^2

Answers

Answered by navtejp2
1

Answer:

Step-by-step explanation:

11- x²

* A * (sin?(1 – 2x2) + cos-(241 – 32)]da

use formula sin-1x + cos-lx =

78* val] - cos -1(1 – 2x2) + – sin -1(2xv1 – x2)]dx

va [1 – 2 cos +1(x) – 2 sin = 2(x)]dx

to

x= [1 – 2(cos –+(x) + sin –+(x)]dx

4x4 [1 – 2 x []dx

= 0

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