integration of sin^2 x
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Answered by
3
we know,
sin²x = 1/2( 1 - cos2x)
use this in integration ,
now,
1/2( 1-cos2x)dx
=1/2dx - 1/2cos2x.dx
=x/2 -1/4sin2x + C
sin²x = 1/2( 1 - cos2x)
use this in integration ,
now,
1/2( 1-cos2x)dx
=1/2dx - 1/2cos2x.dx
=x/2 -1/4sin2x + C
abhi178:
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Answered by
2
sorry by mistake I left 1/2 so..plzz make it ..
write
sin^2x = 1/2 × (1-cos2x)
sorry for the mistake
write
sin^2x = 1/2 × (1-cos2x)
sorry for the mistake
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