Question

integration of sin^2 x upper limit π/3 and lower limit π/6​

Answer 1

Hey mate

integration of sin²x

dy/dx = sin²x

Let sinx=u

So

dy/dx = u² dx

=u^2+1/2+1

= u³

3

Now

= sin³x.

3

=upper limit - Lower limit

= sin³π/3 - sin³π/6

3 3

= sin³60-sin³30°

3

= (√3/2)³-(1/2)³

3

= (3√3/8)-(1/8)

3

= (3√3-1)

8*3

= 3√3-1

24

Thank You

Regards☺️