Integration of (sin 2x √ 1- cos 4x) dx
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Step-by-step explanation:
Let [math]\displaystyle I = \int \dfrac{\sin^2(x) + \cos^2(x)}{\sqrt{1 + \cos(4x)}} \, dx[/math] As, [ math]\sin^2(x) + ... =(1/√2)integ.dx/cos2x.
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