integration of sin^3xcos^3x dx
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hii ✌️
here is ur answer....
∫sin³(x)cos³(x) dx
= ∫sin³(x)(1 - sin²(x))cos(x)dx
Let u = sin(x)
du = cos(x)dx
= ∫u³(1 - u²)du
= ∫u³ - u^5 du
= u⁴/4 - u^6/6 + C
= sin⁴(x)/4 - sin^6 (x)/6 + C
hope it will help you
here is ur answer....
∫sin³(x)cos³(x) dx
= ∫sin³(x)(1 - sin²(x))cos(x)dx
Let u = sin(x)
du = cos(x)dx
= ∫u³(1 - u²)du
= ∫u³ - u^5 du
= u⁴/4 - u^6/6 + C
= sin⁴(x)/4 - sin^6 (x)/6 + C
hope it will help you
Answered by
1
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