Math, asked by yogeswa1592, 1 month ago

Integration of sin^4 x/cos^6 x dx

Answers

Answered by pragnasrimiddela
0

Step-by-step explanation:

Integration of sin^4 x/cos^6 x dx

Integration of (sin^4 x)/(cos^4x × cos^2x)dx

sinx/cosx=tanx

Integration of tan^4x/cos^2xdx

Integration of tan^4xsec^2xdx

assume tanx = t

then differentiation of tanx=t

sec^2(x)dx = dt

Integration of t^4dt

= t^5/5

=tan^5(x)/5

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