integration of (sin^⁴x/cos^⁴x)
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Answer:
if you divide in the first step,then you get tan^⁴x ,
=tan^²x * tan^²x
=tan^²x * (sec^²x -1)
then multiply and integrate
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Step-by-step explanation:bla bla bla bla bla bla bla bla bla bla bla bla bla bla
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