Math, asked by prince873, 11 months ago

integration of sin^4x÷sin^4x+cos^4x dx

Answers

Answered by avash37
0
sin4x/sin4x+cos4​x =sin4x/1-sin2x let1-sin2x = timplies -sin4x dx =dt on substitutingwege get-log(1-sin22x. Was this answer helpful? 0.
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