Math, asked by prince873, 1 year ago

integration of sin^4x÷sin^4x+cos^4x dx

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Answered by avash37

0

sin4x/sin4x+cos4x =sin4x/1-sin2x let1-sin2x = timplies -sin4x dx =dt on substitutingwege get-log(1-sin22x. Was this answer helpful? 0.

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