Math, asked by abhishek9749, 1 year ago

integration of sin cube 2x

Answers

Answered by cutiepie017
2
We know that,   

  sin 3θ =3 sin θ - 4 sin3θ

⇒4 sin3θ = 3 sin θ - sin 3θ

⇒sin3θ =( 3 sin θ - sin 3θ) /4

Let I = ∫sin3 2x dx

=1/4∫3 sin 2x - sin 6x=

1/4-3 cos 2x2 + cos 6x6 + C

cutiepie017: fine
cutiepie017: chandigarh
cutiepie017: 12th
Similar questions