integration of sin cube x
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All you have to do is write the expression as \sin(x)⋅(\text{even power of }\sin), rewrite the even power using the formula \sin^2(x) = 1-\cos^2(x), and apply the substitution u = \cos(x) (i.e. du = -\sin(x)dx). Let's see it in practice: ∫ \sin^3(x)\,dx = ∫ \sin(x)\sin^2(x)\,dx = ∫ \sin(x)(1-\cos^2(x))\,dx = \l.
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