Question

integration of Sin inverse X + Cos inverse X​

Answer 1

hope this helps you☺️☺️☺️

Answer 2

Answer:

,$\int {Sin^{-1}x +Cos^{-1}x}, dx = \dfrac{x\pi }{2}+c$

Step-by-step explanation:

We have-

$I = \int {Sin^{-1}x + Cos^{-1}x } \ dx$

We know that-

$Sin^{-1}x + Cos^{-1}x = \dfrac{\pi }{2}$

So, $I = \int {\dfrac{\pi }{2} } \, dx$

       $= \dfrac{\pi }{2} \int {1} \, dx$

       $= \dfrac{x\pi }{2} + c$

Where c is integral constant.

Hence,$\int {Sin^{-1}x +Cos^{-1}x}, dx = \dfrac{x\pi }{2}+c$