Question

integration of sin x ki power 2 by cos x ki power 4 into main dx​

Answer 1

Answer:

A=−2,B=1/4

B=−1/4,C=−3

B=1/4,C=−3

none of these

Answer :

b

Solution :

We have , I=∫cos4xsin2xdx

⇒I=∫(1−sin2x)2sin2xdx

⇒=∫(cosec2x+sin2x−2)dx

⇒I=−cotx+12(x−sin2x2)−2x+D

⇒I=−cotx−14sin2x−32x+D Hence ,A =−1,B=−14,C=−3

Step-by-step explanation: