Question

Integration of sin6x+sin4x/cos6x+cos4x​

Answer 1

Answer:

Step-by-step explanation:

Using, sin(A)-sin(B) = 2cos((A+B)/2)sin((A-B)/2)  &  cos(A)+cos(B) = 2cos((A+B)/2)cos((A-B)/2)

sin(6x)-sin(4x)/cos(6x)+cos(4x) = 2cos((6x+4x)/2)sin((6x-4x)/2) / 2cos((6x+4x)/2)cos((6x-4x)/2) =

2cos((10x)/2)sin((2x)/2) / 2cos((10x)/2)cos((2x)/2) = sin(2x/2) / cos(2x/2) = tan (2x/2) = tan (x)

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Answer 2

Answer:

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Step-by-step explanation:

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