Question

❤ integration of tanx ??????

​

Answer 1

$\huge\underline\mathfrak\black{To Find }$

∫tanx dx

$\huge\underline\mathfrak\blue{Answer }$

∫tanx dx

= ∫(sinx/cosx )dx

let cosx = t

then , dt /dx = -sinx

∫(sinx/ t )× (dt /-sinx)

= -∫dt/t

= -log (t)

= -log(cosx)

= log (secx )

I hope it helps you!

Answer 2

Answer:

hey,see the attachment

Step-by-step explanation:

the chalk i am using is lite

so its not very clear