Question

integration of this question as soon as possible​

Answer 1

Answer:

$∫\sqrt{1 - sin2x} dx \\ \\ ∫\sqrt{ {(sinx)}^{2} + {(cosx)}^{2} -2sinx \: cosx } \: \: dx \\ \\ ∫\sqrt{(sinx - cosx) ^{2} } \: \: dx \\ \\ ∫sinx - cosx \: dx \\ \\ integrate \: w.t.x \\ \\ - cosx - sinx + c$