Question

integration of this question as soon as possible​

Answer 1

$\int \frac{1}{1-sinx}dx\\</p><p>=\int \frac{1+\sin x}{1-sin^2 x}dx\\</p><p>=\int {\frac{1+sin x}{cos^2x}}dx\\</p><p>=\int {\sec^2 x+ \tan x\sec x}dx\\</p><p>=\tan x+ \sec x+c$