Question

Integration of under root
1+sintheta d theta =?​

Answer 1

Given :- (mn)³ ÷ p³

To Find :- (mn)³ ÷ p³ = ?

Solution :-

(mn)³ ÷ p³ = $\frac{m {}^{3} n {}^{3} }{p3}$

Hence, (mn)³ ÷ p³ = $\frac{m {}^{3} n {}^{3} }{p3}$

Hence, the final answer is $\frac{m {}^{3} n {}^{3} }{p3}$