Question

Integration of (√x - 1/√x)^2 is

Answer 1

$\textbf{Hey there}$!

$\textbf{Solution}$:

= $\int ( { \sqrt{x } })^{2} + ({ \frac{1}{ \sqrt{x} } })^{2} - 2 \sqrt({x} )( \frac{1}{ \sqrt{x} } ).dx$

= $\int(x + \frac{1}{x} - 2).dx$

= $\int(xdx + \frac{1}{x} - 2).dx$

= $\int(xdx + \int \frac{1}{x} .dx - 2\int(dx)$

I = $\frac{1}{2} {x}^{2} + log |x| - 2x + c$

#Be Brainly.