Math, asked by anshisharam, 1 year ago

Integration of (√x - 1/√x)^2 is

Answers

Answered by BrainlyWarrior
6
\textbf{Hey there}!

\textbf{Solution}:

= \int ( { \sqrt{x } })^{2} + ({ \frac{1}{ \sqrt{x} } })^{2} - 2 \sqrt({x} )( \frac{1}{ \sqrt{x} } ).dx

= \int(x + \frac{1}{x} - 2).dx

= \int(xdx + \frac{1}{x} - 2).dx

= \int(xdx + \int \frac{1}{x} .dx - 2\int(dx)

I =  \frac{1}{2} {x}^{2} + log |x| - 2x + c

#Be Brainly.
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