Question

Integration of x+1/x whole cube DX

Answer 1

Step-by-step explanation:

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Answer 2

We will first open the bracket

(x^2+1)^3/x^3

(x^6+1+3x^4+3x^2)/x^3

[ (a+b)^3 = a^3 + b^3 + 3ab (a+b) ]

x^3 + (1/x^3) + 3x + 3/x

Now integrate this eqn

We get

x^4/4 - 2/x^2 + 3x^2/2 + 3lnx

I am srry for doing it directly as i assume u know all the conversions