Question

integration of x^2+4x+4/(√x-1)^3(√x^3-1)​

Answer 1

Step-by-step explanation:

∫x2−4x+13dx

=∫(x−2)2−4+13dx

=∫(x−2)2+(3)2dx

=31tan−1(3x−2)+C

Hence ∫x2−4x+13dx=31tan−1(3x−2)+C