Math, asked by sarveshc129, 9 months ago

integration of x^9sec^2x^10​

Answers

Answered by senboni123456
1

Step-by-step explanation:

We have,

 \int {x}^{9}  \sec^{2} ( {x}^{10} ) dx

 =  \frac{1}{10}  \int10 {x}^{9}  \sec^{2} ( {x}^{10} ) dx

Let x^10 = t => 10 x^9 dx = dt

  =  \frac{1}{10}  \int \sec^{2} (t) dt

 =  \frac{1}{10}  \tan(t)  + c

 =  \frac{1}{10}  \tan( {x}^{10} ) +  c

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