Math, asked by bajpaiaayush202, 11 months ago

integration of x log 1 + 1 upon x dx

Answers

Answered by ᎷíssGℓαмσƦσυs

0

log 1 = 0

x×0=0

1/xdx

integration 1/x dx

= log x + c

bajpaiaayush202: thay ws bot question

bajpaiaayush202: not*

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