integration of x square cos cube x dx
pls explain step by step
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Answer:
cos^3x(2x)-x^2(3cos^2x)(sinx)
Step-by-step explanation:
firstly applying product law and along with power chain rule
x^2(cos^3x)'+cos^3x(x^2)'
-x^2(3cos^2x{sinx})+cos^3x×2x
cos^3x(2x)-x^2(3cos^2x)(sinx)
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